Find and equation of the circle with center at (0,0) that passes through the poijt (5,2)
Which method have you been taught to find the circle for this basic question?
I haven't learned how to do this.
I don't understand.
Are you in a course where this on the curriculum?
How do they expect you to do this if you have not learned it, or have not been taught?
I don't know but that's why I'm asking on this website.
basic equation with centre (0,0) and radius r is
x^2 + y^2 = r^2
since (5,2) lies on this
25 + 4 = r^2 = 29
x^2 + y^2 = 29
To find the equation of a circle with its center at (0,0) and passing through the point (5,2), we can use the general equation of a circle:
(x - h)^2 + (y - k)^2 = r^2
Where (h,k) represents the center of the circle, and r represents the radius.
Since the center of the circle is (0,0), our equation becomes:
(x - 0)^2 + (y - 0)^2 = r^2
Simplifying it further, we have:
x^2 + y^2 = r^2
Now we need to determine the radius, r. We know that the circle passes through the point (5,2), so we can substitute these coordinates into the equation:
5^2 + 2^2 = r^2
25 + 4 = r^2
29 = r^2
Therefore, the equation of the circle with its center at (0,0) and passing through the point (5,2) is:
x^2 + y^2 = 29