A gas occupying 29 mL at standard conditions is heated to 14◦C while the pressure is reduced to 0.98682 atm. What is the new volume occupied by the gas?

To find the new volume occupied by the gas, we can use the combined gas law, which states that the ratio of the initial pressure to the final pressure is equal to the ratio of the initial volume to the final volume, assuming the amount of gas and temperature remain constant.

The combined gas law formula is:

(P₁ * V₁) / (T₁) = (P₂ * V₂) / (T₂)

Where:
P₁ = initial pressure
V₁ = initial volume
T₁ = initial temperature
P₂ = final pressure
V₂ = final volume
T₂ = final temperature

Let's plug in the given values:

P₁ = 1 atm (standard conditions)
V₁ = 29 mL
T₁ = 273 K (standard conditions)
P₂ = 0.98682 atm
T₂ = 14°C + 273 = 287 K

Now we can solve for V₂:

(1 atm * 29 mL) / (273 K) = (0.98682 atm * V₂) / (287 K)

Cross-multiplying the equation:

29 mL * 287 K * 0.98682 atm = V₂ * 273 K

Simplifying the equation:

V₂ = (29 mL * 287 K * 0.98682 atm) / (273 K)

Performing the calculation:

V₂ ≈ 33.3 mL

Therefore, the new volume occupied by the gas is approximately 33.3 mL.