calculate the molarity of cl- ions in a solution made from mixing 50.0 ml of a 0.100 m/l solution of ferric chloride with 50.0 ml of a 0.500 mol/l solution of ammonium chloride

To calculate the molarity of Cl- ions in the solution, we can use the following formula:

Molarity (M) = moles of solute / volume of solution (in liters)

First, we need to calculate the moles of Cl- ions in both the ferric chloride and ammonium chloride solutions.

For the ferric chloride solution:
moles of ferric chloride (FeCl3) = molarity (M) × volume (L)
moles of Cl- ions in ferric chloride = moles of ferric chloride × 3

moles of Cl- ions in ferric chloride = 0.100 M × 0.0500 L × 3

For the ammonium chloride solution:
moles of ammonium chloride (NH4Cl) = molarity (M) × volume (L)
moles of Cl- ions in ammonium chloride = moles of ammonium chloride

moles of Cl- ions in ammonium chloride = 0.500 M × 0.0500 L

Now, add the moles of Cl- ions from both solutions together to get the total moles of Cl- ions:

total moles of Cl- ions = moles of Cl- ions in ferric chloride + moles of Cl- ions in ammonium chloride

Substitute the derived values into the equation:

total moles of Cl- ions = (0.100 M × 0.0500 L × 3) + (0.500 M × 0.0500 L)

Next, calculate the total volume of the solution:

total volume of solution = volume of ferric chloride solution + volume of ammonium chloride solution

total volume of solution = 0.0500 L + 0.0500 L

Finally, use the molarity formula to find the molarity of Cl- ions:

Molarity of Cl- ions = total moles of Cl- ions / total volume of solution

Molarity of Cl- ions = [(0.100 M × 0.0500 L × 3) + (0.500 M × 0.0500 L)] / (0.0500 L + 0.0500 L)

Simplifying the equation and calculating will give you the final answer for the molarity of Cl- ions in the solution.