a body projected with velocity 30m/s an angle 30¡ã with horizontal maximum height attained by he object is.........?
A mass is launched at 30 degree to the horizontal with a speed 25 metre per second. What is the maximum height obtained??
To find the maximum height attained by an object projected at an angle with a certain velocity, we can use the equations of motion for projectile motion.
The maximum height can be found using the formula:
Hmax = (v^2 * sin^2θ) / (2 * g)
Where:
Hmax is the maximum height,
v is the initial velocity,
θ is the angle of projection,
and g is the acceleration due to gravity (approximately 9.8 m/s^2 on Earth).
Using the given values, we can substitute them into the formula to calculate the maximum height.
v = 30 m/s
θ = 30°
Let's plug these values into the formula:
Hmax = (30^2 * sin^2(30°)) / (2 * 9.8)
Calculating further:
Hmax = (900 * (1/2)^2) / (19.6)
= (900 * 1/4) / (19.6)
= 225 / 19.6
≈ 11.48 meters
Therefore, the maximum height attained by the object is approximately 11.48 meters.
2sin-ecos
well, the upward component is
15 m/s, so the height is
h(t) = 15t - 4.9t^2
So, just find the vertex of that parabola.