A 2.50m -long, 450g rope pulls a 10.0kg block of ice across a horizontal, frictionless surface. The block accelerates at 2.50m/s2 . How much force pulls forward on the rope?

F = m A

F = (10.45)(2.5)

To determine the force pulling forward on the rope, we can use Newton's second law of motion, which states that the force (F) is equal to the mass (m) multiplied by the acceleration (a):

F = m * a

In this case, the mass of the block (m) is given as 10.0 kg, and the acceleration (a) is given as 2.50 m/s^2. So, we can substitute these values into the equation:

F = 10.0 kg * 2.50 m/s^2

Calculating this gives us the force (F) exerted on the block:

F = 25.0 N

Since the rope is pulling the block, the magnitude of the force exerted on the rope is also 25.0 N. Thus, the force pulling forward on the rope is 25.0 Newtons.