The volume of a gas with a pressure of 1.2 atm increases from 1.0 L to 4.0 L. What is the final pressure of the gas, assuming constant temperature?
To solve this problem, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional at a constant temperature.
Boyle's Law can be represented by the equation: P₁V₁ = P₂V₂, where P₁ and V₁ are the initial pressure and volume, and P₂ and V₂ are the final pressure and volume.
Given:
Initial pressure, P₁ = 1.2 atm
Initial volume, V₁ = 1.0 L
Final volume, V₂ = 4.0 L
We can rearrange the equation to solve for the final pressure, P₂.
P₁V₁ = P₂V₂
P₂ = (P₁V₁) / V₂
Substituting the given values:
P₂ = (1.2 atm * 1.0 L) / 4.0 L
P₂ = 1.2 atm / 4.0
P₂ = 0.3 atm
Therefore, the final pressure of the gas, assuming constant temperature, is 0.3 atm.
To find the final pressure of the gas, we can use Boyle's Law, which states that the volume and pressure of a gas are inversely proportional at constant temperature. Boyle's Law equation is as follows:
P₁V₁ = P₂V₂
Where P₁ and V₁ are the initial pressure and volume, and P₂ and V₂ are the final pressure and volume.
In this case, we know the initial pressure is 1.2 atm and the initial volume is 1.0 L. The final volume, V₂, is 4.0 L. We need to find the final pressure, P₂.
Using the Boyle's Law equation, we can rearrange it to solve for P₂:
P₂ = (P₁V₁) / V₂
Plugging in the values we have:
P₂ = (1.2 atm * 1.0 L) / 4.0 L
P₂ = 0.3 atm
Therefore, the final pressure of the gas, assuming constant temperature, is 0.3 atm.