What weight of O is produced when 3.00 g of KClO3 (s) is decomposed according to the reaction 2KClO3(s) 2KCl(s)+ 3O2(g)?
A. 0.392g
B. 0.587g
C. 0.783g
D. 1.17g
add a quick explanation, thnx
Balance the equation. You have that.
mols KClO3 = grams/molar mass = ?
Use the coefficients in the balanced equation to convert mols KClO3 to mols O2. That's mols KClO3 x (3 mols O2/2 mols KClO3) = mols KClO3 x 3/2 = ?
Now convert mols O2 to grams. grams = mols x molar mass = ?
What weight of O is produced when 3.00 g of KClO3 (s) is decomposed according to the reaction 2KClO3(s) 2KCl(s)+ 3O2(g)?
A. 0.392g
B. 0.587g
C. 0.783g
D. 1.17g
add a quick explanation, thnx
CHEMISTRY - DrBob222, Thursday, March 26, 2015 at 10:11pm
Balance the equation. You have that.
mols KClO3 = grams/molar mass = ?
Use the coefficients in the balanced equation to convert mols KClO3 to mols O2. That's mols KClO3 x (3 mols O2/2 mols KClO3) = mols KClO3 x 3/2 = ?
Now convert mols O2 to grams. grams = mols x molar mass = ?
D. 1.17g
Thanks
To find the weight of O produced when 3.00 g of KClO3 is decomposed, we can start by calculating the molar mass of KClO3.
Step 1: Calculate the molar mass of KClO3
The molar mass of potassium chloride (KCl) is approximately 74.55 g/mol. The molar mass of oxygen (O) is approximately 16.00 g/mol. Since KClO3 has one potassium atom (K), one chlorine atom (Cl), and three oxygen atoms (O), we can add the molar masses to find the molar mass of KClO3.
1 × (74.55 g/mol) + 1 × (35.45 g/mol) + 3 × (16.00 g/mol) = 122.55 g/mol
Step 2: Calculate the number of moles of KClO3 used
To find the number of moles, we can use the formula:
moles = mass / molar mass
moles = 3.00 g / 122.55 g/mol ≈ 0.024 mol
Step 3: Use the balanced equation to find the ratio of moles of O to KClO3
According to the balanced equation, 2 moles of KClO3 produce 3 moles of O:
2KClO3(s) → 2KCl(s) + 3O2(g)
So the ratio is 3 moles of O per 2 moles of KClO3.
Step 4: Calculate the number of moles of O produced
Using the ratio from Step 3, we can convert the moles of KClO3 to moles of O:
moles of O = (moles of KClO3) × (3 moles of O / 2 moles of KClO3)
moles of O = 0.024 mol × (3 mol O / 2 mol KClO3) ≈ 0.036 mol
Step 5: Calculate the weight of O produced
To find the weight of O produced, we can use the formula:
weight = moles × molar mass
weight = 0.036 mol × 16.00 g/mol ≈ 0.576 g
Therefore, the weight of O produced when 3.00 g of KClO3 is decomposed is approximately 0.576 g.
Looking at the answer choices provided, the closest option is B. 0.587 g.