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chemistry

Calculate the pH at the stoichiometric point of a titration of 25.0 mL of 0.120 M benzoic acid with 0.0230 M NaOH

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  1. Calculate mL NaOH needed to reach the equivalence point.
    mLacid x Macid = mLNaOH x MNaOH

    Let HBz = benzoic acid then
    HBz + NaOH ==> NaBz + H2O

    The pH at the equivalence point is determined by the hydrolysis of the salt, NaBz. The (NaBz) = molsNaBz/L = ?. I will call that z.

    .......Bz^- + HOH --> HBz + OH^-
    I......z...............0.....0
    C......-x..............x.....x
    E......z-x.............x.....x

    Kb for Bz^- = (Kw/Ka for HBz) = (x)(x)/(z-x)
    Substitute and solve for x = (OH^-) and convert that to pH.

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