How many kg of Glaubers salt (Na2SO4. 10 H2O) will be obtained from 250 kg of Na2SO4
To calculate the amount of Glaubers salt (Na2SO4.10H2O) obtained from a given mass of Na2SO4, we need to find the molar ratio between the two compounds.
First, we need to determine the molar mass of Na2SO4 and Glaubers salt:
1 mole of Na2SO4 = (2 × atomic mass of Na) + atomic mass of S + (4 × atomic mass of O)
= (2 × 23) + 32 + (4 × 16)
= 46 + 32 + 64
= 142 g/mol
1 mole of Na2SO4.10H2O = (2 × atomic mass of Na) + atomic mass of S + (4 × atomic mass of O) + (10 × [(2 × atomic mass of H) + atomic mass of O])
= (2 × 23) + 32 + (4 × 16) + (10 × [(2 × 1) + 16])
= 46 + 32 + 64 + (10 × [2 + 16])
= 46 + 32 + 64 + (10 × 18)
= 46 + 32 + 64 + 180
= 322 g/mol
Now, we can find the molar ratio of Na2SO4 to Na2SO4.10H2O:
Molar Ratio = (molar mass of Na2SO4) / (molar mass of Na2SO4.10H2O)
= 142 g/mol / 322 g/mol
≈ 0.441
To calculate the mass of Glaubers salt obtained from 250 kg of Na2SO4, we multiply the molar ratio by the mass of Na2SO4:
Mass of Glaubers salt = (Molar Ratio) × (Mass of Na2SO4)
= 0.441 × 250 kg
= 110.25 kg
Therefore, approximately 110.25 kg of Glaubers salt (Na2SO4.10H2O) will be obtained from 250 kg of Na2SO4.