Question

calculate the solubility of SrF2 (ksp=7.9E-10) in 0.100 M Sr(NO3)2 ?

The answer is 4.44E-5 M how do you get that?

I Have no clue

I saw the setup but it doesnt get 4.44E-5 M

Answer 1

It most certainly does. I worked it and it produced exactly that number. If you will post your work I will find the error but I expect I can tell you without looking at your work.

You probably wrote (0.1)(2x). It should be (0.1)(2x)^2 and x = 4.44E-5M big as life.