Two pea plants are crossed. One is homozygous recessive for long (long is dominant and short is recessive) and the other is heterozygous. If 100 pea plant offspring are produced, how many of them will be long?
The genotypes are ss and Ls.
Use a Punnett square.
https://www.google.com/search?client=safari&rls=en&q=punnett+square&ie=UTF-8&oe=UTF-8&gws_rd=ssl
To determine the number of pea plant offspring that will be long, we need to understand the principles of Mendelian genetics and the Punnett square.
Let's first define the genotypes of the parent pea plants:
- One parent is homozygous recessive for short (ll).
- The other parent is heterozygous for long (Ll).
Now, let's create a Punnett square to determine the possible combinations of alleles for the offspring:
L l
-----------------------
l | Ll ll
l | Ll ll
In this Punnett square, the columns represent the possible alleles from one parent, while the rows represent the alleles from the other parent. Crossing these alleles will give us the possible genotypes of the offspring.
The results of the Punnett square show that there are two different genotypes for long offspring: Ll and Ll. Since long (L) is dominant over short (l), both genotypes will exhibit the long phenotype.
Therefore, in this particular cross, all of the 100 pea plant offspring will be long.