Chemistry

A student tested the effect of temperature on the decomposition of N2O5. He found that the rate of the reaction at a lower temperature was 4.2 x 10–3 s–1 and the rate at a higher temperature was 1.6 x 101 s–1. What is wrong with the student's data?

A. Nothing. Rate constants are constant for a given reaction temperature, and vary as temperatures change.
B. The rate constant must be less than 1.
C. The rate constant should be the same for each reaction.
D. The rate constant must be greater than 1.

  1. 👍 0
  2. 👎 0
  3. 👁 640

Respond to this Question

First Name

Your Response

Similar Questions

  1. chemistry

    Values of the rate constant for the decomposition of N2O5 at four different temperatures are as follows: T(K) k(s^-1) 658....2.14*10^5 673....3.23*10^5 688....4.81*10^5 703....7.03*10^5 The activation energy is 1.02*10^2 kJ/mol.

  2. chemistry

    When N2O5 (g) is heated it dissociates into N2O3 (g) and O2 (g) according to the following reaction: N2O5 (g) N2O3 (g) + O2 (g) Kc=7.75 at a given temperature. The N2O3 (g) dissociates to give N2O (g) and O2 (g) according the

  3. org. chem.

    A student who was isolating aspirin stopped the experiment after the filtration step with alumina. One week later, the methanol was evaporated and the experiment was completed. The melting point of the aspirin was found to be

  4. chemistry

    The decomposition of N2O5 proceeds according to the following equation 2 N2O5(g) → 4 NO2(g) + O2(g). The rate constant, k, for the reaction at 298 K is 2.20 x 10-3 min-1. If a reaction is set up in a vessel at 298 K, with an

  1. chemistry

    For the decomposition of gaseous dinitrogen pentoxide (shownbelow), 2 N2O5(g).....> 4NO2(g) + O2(g) the rate constant is k = 2.8 10-3 s-1 at 60°C. The initial concentration of N2O5 is 1.52 mol/L. (a) What is [N2O5] after 5.00

  2. Chem

    Calculate delta H for the formation of one mole of N2O5 from the elements at 25 degrees C using the following data. 2H2 + O2 - 2H2O delta H = -571.6 kJ N2O5 + H2O - 2HNO3 deltaH = -73.7 kJ 1/2N2 + 3/2O2 + 1/2H2 - HNO3 delta H =

  3. Chemistry

    Consider the following two thermochemical equations N2+2.5O2-> N2O5(s) Delta H=xkJ N2+2.5O2-> N2O5(g) Delta H=ykJ The enthalpy change in kJ for the sublimation of one mole of N205 solid to gas would be represented by the quantity

  4. Chemistry

    N2O5 is an unstable gas that decomposes according to the following reaction: 2N2O3(g) ---> 4NO2(g) + O2(g) What would be the total pressure of gases present if a 10.0L container at 22.0 degree centigrade begins with 0.400 atm of

  1. College Chemistry- Hess's Law

    Nitrogen oxides undergo many interesting reactions in the environment and in industry. Given the following information, calculate H for the overall equation: 2 NO2(g) + 1/2 O2(g) = N2O5(s). 2 NO(g) + 3/2 O2(g) = N2O5(s), H =

  2. Chemistry

    The gas phase decomposition of dinitrogen pentoxide at 335 K N2O5(g) 2 NO2(g) + ½ O2(g) is first order in N2O5. During one experiment it was found that when the initial concentration of N2O5 was 0.218 M, the concentration of N2O5

  3. Chemistry

    From the following data for the decomposition of N2O5 in CCl4 solution at 48 C, show that it is a first order reaction. t (mins) 10 15 20 25  VCO2 6.30 8.95 11.40 13.5 34.75

  4. Chemistry

    The reaction, N2O5 = 2NO2+1/2O2 is first order in N2O5 with rate constant 6.2 x 10^-4 s^-1. What is the value of rate of reaction when [N2O5] = 1.25 mol L^-1 s^-1 ?

You can view more similar questions or ask a new question.