physics

a ball was thrown vertically upward from the ground and reaches a height of 50 meters. a) with what speed was it thrown?
b) how long will it remain in the air?

  1. 👍
  2. 👎
  3. 👁
  1. since h(t) = vt - 4.9t^2, the vertex is at t = v/9.8

    so,

    v(v/9.8) - 4.9(v/9.8)^2 = 50
    v = 31.305 m/s

    Now you can find how long it was in the air. Namely, twice as long as it took to reach its max height.

    1. 👍
    2. 👎

Respond to this Question

First Name

Your Response

Similar Questions

  1. science

    a ball is thrown straight upward and returns to the thrower's hand after 3.00s in the air. A second ball is thrown at an angle of 30.0 deg with the horizontal. At what speed must the second ball be thrown so that it reached the

  2. Algebra

    THe function h(t)=-16t^2+v0t+h0 describes the height in feet above the ground h(t) of an object thrown vertically from a height of h0 feet, with an initial velocity of v0 feet per second, if there is no air friction and t is the

  3. phy

    A blue ball is thrown upward with an initial speed of 20.6 m/s, from a height of 0.8 meters above the ground. 2.5 seconds after the blue ball is thrown, a red ball is thrown down with an initial speed of 8.2 m/s from a height of

  4. Physics

    A red ball is thrown down with an initial speed of 1.3 m/s from a height of 28.0 meters above the ground. Then, 0.6 seconds after the red ball is thrown, a blue ball is thrown upward with an initial speed of 24.7 m/s, from a

  1. pre-calc

    Physics: a ball is thrown vertically upward with an initial velocity of 80 feet per second. the distance (in feet) of the ball from the ground after t seconds if s=80t-16tt^2 a) draw the illustration b) for what time interval is

  2. Physics

    A ball is thrown straight upward and returns to the thrower's hand after 2.30 s in the air. A second ball is thrown at an angle of 42.0° with the horizontal. At what speed must the second ball be thrown so that it reaches the

  3. Algebra

    THe function h(t)=-16t^2+v0t+h0 describes the height in feet above the ground h(t) of an object thrown vertically from a height of h0 feet, with an initial velocity of v0 feet per second, if there is no air friction and t is the

  4. Pre-Calc

    ball thrown vertically upward with an initial velocity of 80 ft per second. The distance s(in ft) of the ball from the ground after t seconds is s=80t-16t^2. a. draw the illustration. b. for what time interval is ball more than 96

  1. Calculus

    If a ball is thrown vertically upward from the roof of 32 foot building with a velocity of 112 ft/sec, its height after t seconds is s(t)=32+112t–16t2 . What is the maximum height the ball reaches?What is the velocity of the

  2. Math( help please ! )

    The height of a ball thrown vertically upward from a rooftop is modelled by y=-5t^2+20t+50 , where h(t) is the ball's height above the ground , in meters , at time t seconds after the throw a) Determine the max height of the ball

  3. math

    A rock is thrown vertically up from the ground with a velocity of 24 meters per second, and it reaches a height of 2+24t-4.9tsquare after t secounds. A. How many seconds after the rock is thrown will it reach its maximum height?

  4. Physic!

    A blue ball is thrown upward with an initial speed of 23 m/s, from a height of 0.5 meters above the ground. 2.8 seconds after the blue ball is thrown, a red ball is thrown down with an initial speed of 6.6 m/s from a height of

You can view more similar questions or ask a new question.