In your own words, describe how you would calculate the concentration of green pigment. Assume that your 1/100 solution had an Absorbance of 0.8 and that the extinction coefficient for the green pigment is = 20 mM-1cm-1. Remember the Beer Lambert Law!
http://en.wikipedia.org/wiki/Molar_absorptivity
Absorbance = epsilon x length of cell x concn in mols/liter.
To calculate the concentration of the green pigment, we can use the Beer Lambert Law, which relates the concentration of a substance to its absorbance. The equation for the Beer Lambert Law is A = εlc, where A is the absorbance, ε is the molar absorptivity (also known as the extinction coefficient), l is the path length of the light through the solution, and c is the concentration of the substance.
In this case, we have the following information:
- Absorbance, A = 0.8
- Extinction coefficient, ε = 20 mM-1cm-1
We need to find the concentration, c.
Rearranging the Beer Lambert Law equation, we have c = A / (ε * l).
Since we are not given the path length l in this question, I will assume a standard path length of 1 cm.
By substituting the known values into the equation, we get:
c = 0.8 / (20 mM-1cm-1 * 1 cm)
c = 0.8 / 20 mM-1
c = 0.04 mM
Therefore, the concentration of the green pigment is 0.04 mM.