Algebra

An artifact was found and tested for its carbon-14 content. If 76% of the original carbon-14 was still present, what is its probable age (to the nearest 100 years)? (Carbon-14 has a half-life of 5,730 years.)

asked by Anonymous
  1. .76 = 1 (1/2)^(t/5730)
    log both sides:
    log .76 = (t/5730) log .5
    t/5730 = log .76/log .5 = .39592...
    t = 2268.67 years
    or
    t = appr 2300 years, correct to the nearest 100 yrs.

    posted by Reiny

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