If 2 objects of unequal masses are hung vertically over a frictionless pulley of negligible mass. determine the magnitude of the acceleration of the two objects and the tension in the light weight cord

To determine the magnitude of the acceleration and the tension in the cord, we can use Newton's second law of motion and the principle of conservation of energy.

First, let's assign variables to the given information:
- Mass of object 1: m1
- Mass of object 2: m2
- Acceleration of the system: a
- Tension in the cord: T

According to Newton's second law, the force acting on an object is equal to its mass multiplied by its acceleration:

Force = mass * acceleration

For object 1:
T - m1 * g = m1 * a -- (equation 1)
Here, T is the tension in the cord, m1 is the mass of object 1, g is the acceleration due to gravity, and a is the common acceleration of the system. The minus sign is because the direction of the force on object 1 is opposite to the direction of its acceleration.

For object 2:
m2 * g - T = m2 * a -- (equation 2)
Here, T is the tension in the cord, m2 is the mass of object 2, g is the acceleration due to gravity, and a is the common acceleration of the system. The minus sign is because the direction of the force on object 2 is opposite to the direction of its acceleration.

Next, we can use the principle of conservation of energy. As the system is frictionless, the total mechanical energy remains constant. The potential energy gained by object 1 is equal to the potential energy lost by object 2:

m1 * g * h = m2 * g * h
Here, h is the vertical height moved by both objects, which is the same for both.

Now we can solve the above equations simultaneously. Let's substitute h using the principle of conservation of energy. Dividing both sides by g, we get:

m1 * h = m2 * h

This shows that the mass terms cancel out, which means the magnitude of acceleration (a) does not depend on the masses of the objects.

Putting the value of h back into equations 1 and 2, we get:

T - m1 * g = m1 * a -- (equation 1)
m2 * g - T = m2 * a -- (equation 2)

From equations 1 and 2, we can solve for T and a:

T = (m2 - m1) * g / (m1 + m2) -- (equation 3)
a = (m2 - m1) * g / (m1 + m2) -- (equation 4)

Equation 3 gives us the tension in the cord (T), and equation 4 gives us the magnitude of the acceleration (a).

By substituting the masses (m1 and m2) and the acceleration due to gravity (g) into equations 3 and 4, you can calculate the values of T and a for a specific problem.