Calculate the work done on the system when 1.00 mol of gas held behind a piston expands irriversibly from a volume of 10.0dm^3 against an external pressure of 1.00 bar?
2.23
To calculate the work done on the system during an irreversible expansion, you need to use the formula:
Work = -PΔV
Where:
- Work is the work done on the system.
- P is the external pressure.
- ΔV is the change in volume.
In this case, the external pressure is given as 1.00 bar, which is equal to 100,000 Pa (since 1 bar = 100,000 Pa).
The change in volume (ΔV) can be calculated by subtracting the final volume from the initial volume.
Given that the initial volume is 10.0 dm^3, which is equivalent to 10.0 L, we need to convert it to cubic meters to match the SI unit of pressure (Pa).
1 L is equal to 0.001 m^3, so 10.0 L is equal to 0.010 m^3.
Let's calculate the change in volume (ΔV) and the work done on the system using the given values:
ΔV = final volume - initial volume
= ?
Work = -PΔV
= -100,000 Pa * ΔV
Unfortunately, the final volume is not provided in the question. You would need to know the final volume to calculate the change in volume (ΔV) and the work done on the system.