5. Find the x and y intercepts of each linear equation. Be sure to write your answers as ordered pairs.

a.y=3x-6
b.6y=-x+2

Set x = 0 and y = 0 to find the intercepts.

will that get me 2 thingys for each.?

Again, you should show your own answer first, but I'll show you (a). Afterwards, you should try (b) and post your answer. I'll tell you if it's correct!

All you do to find an x-intercept is plug a zero in for the y. To find the y-intercept, you plug in a zero for the x.

So, on (a):

X intercept:

y=3x-6
0=3x-6
+6 +6
6=3x
divide each side by 3, and x equals 2. Therefore, the x intercept is (2,0)

For y:
y=3(0)-6
y=0-6
y=-6, so the y-intercept is (0,-6)

would it be (1/3,0) and (-2,0)

You got it! :]

Actually, for equation (a), the x-intercept is (2, 0) and the y-intercept is (0, -6) as we calculated earlier.

Now let's move on to equation (b):

6y = -x + 2

To find the x-intercept, we set y = 0.

6(0) = -x + 2

0 = -x + 2

To isolate x, we subtract 2 from both sides:

-2 = -x

To get x alone, we multiply both sides by -1, which changes the sign:

2 = x

So the x-intercept is (2, 0).

To find the y-intercept, we set x = 0.

6y = -(0) + 2

6y = 2

Divide both sides by 6 to isolate y:

y = 2/6

Simplifying the fraction, we get:

y = 1/3

So the y-intercept is (0, 1/3).

Therefore, the x-intercept of equation (b) is (2, 0) and the y-intercept is (0, 1/3). Good job!