Factor the following. You will earn 5 points for each polynomial that is factored correctly. Please label your individual answers with a – f.
a.) 4x2 - 25
b.) 3x2 + 6y
c.) x^2 - 7x + 10
d.) 2x^2 - 9x – 18
e.) 2ax + 6bx + ay + 3by
f.) 6x^2 + 12x – 48
*Can you help me with all of them.?
Do you have any of the answers that you've tried on your own first? Maybe then I could tell you if they are right, or even where you are going wrong. :)
It's just I only have 4 minutes left and then I have to get off.Can't you just tell me please?How about this I will do the last 2 but can you do the rest.?
I actually got 10 more minutes but can you still do them because now I have 8 minutes left....
Okay, go ahead and show me what you got on the last two.
ok but are you going to do the other ones.?
I'm working on them. I just don't want to hand you the answers. I'm still in school, and it's just that I always wanted answers to be fed to me, too, but I've come to find that by test day, it was a terrible idea.
ok;but while you are working on those can you please check this to see if it is correct.?
Use the following quadratic equation to complete parts a – c below.
3x^2 + 2x - 5 = 0.
a. Solve by factoring.
b. Solve using the quadratic formula.
c. Describe the relationship between your answers for parts a and b.
Here is what I got:
a.(3x-1)(x+4)
b.-1
c.The relationship between these 2 are that they both have negatives.
The factors are wrong. You need a five in the last parenthesis.
here is what I got:
e.) 2ax + 6bx + ay + 3by = (2a+6b)(x+3y)
f.) 6x^2 + 12x – 48 = (3x+12)(2x-4)
*Is this correct.?
COME ON TRISH!WHERE ARE YOU PLEASE>!!!!!
I apologize for the delay. Here are the factorizations for the given polynomials:
a) 4x^2 - 25 = (2x - 5)(2x + 5)
b) 3x^2 + 6y = 3(x^2 + 2y)
c) x^2 - 7x + 10 = (x - 5)(x - 2)
d) 2x^2 - 9x - 18 = (2x + 3)(x - 6)
e) 2ax + 6bx + ay + 3by = (2a + 6b)(x + y)
f) 6x^2 + 12x - 48 = 6(x^2 + 2x - 8) = 6(x + 4)(x - 2)
For the quadratic equation 3x^2 + 2x - 5 = 0:
a) Solve by factoring:
To solve by factoring, we need to find two binomials that multiply to give the quadratic equation. In this case, we have (3x - 1)(x + 5) = 0.
b) Solve using the quadratic formula:
The quadratic formula is x = (-b ± √(b^2 - 4ac)) / (2a). In this case, a = 3, b = 2, and c = -5. Plugging in these values into the formula, we get x = (-2 ± √(2^2 - 4(3)(-5))) / (2(3)). Simplifying further, x = (-2 ± √(4 + 60)) / 6, which becomes x = (-2 ± √64) / 6. So x = (-2 ± 8) / 6, which gives us two solutions: x = 1 and x = -5/3.
c) The relationship between the answers for parts a and b:
In both parts a and b, we found two solutions for the quadratic equation. The relationship between the answers is that the solutions obtained through factoring and using the quadratic formula are equivalent. In this case, both methods yield the same solutions: x = 1 and x = -5/3.
I hope this helps! Let me know if you have any further questions.