0.24g of a volatile substance,upon vaporisation,gives 45ml vapour at NTP what will be the vapour density of the substance?
First find the molar mass of the substance at NTP
Mass= 22400×0.24/45
=119.46
Density=M mass/2
=119.46/2
= 59.73
Answer= 59.73
Use ideal gas equations St NTP to find molar mass
PV=nRT
To calculate the vapor density of a substance, you need to know the molar mass of the substance and the volume of the vapor at a given temperature and pressure.
Here's how you can solve the problem step by step:
Step 1: Calculate the number of moles of the substance.
- Use the formula: \( \text{{moles}} = \frac{{\text{{mass (g)}}}}{{\text{{molar mass (g/mol)}}}} \)
- Given: mass = 0.24 g
To find the molar mass of the substance, you will need more information such as the identity of the substance or its chemical formula. Can you provide that information?
Step 2: Calculate the vapor density.
- Use the formula: \( \text{{vapor density}} = \frac{{\text{{molar mass (g/mol)}}}}{{\text{{volume of vapor (L)}}}} \)
- Given: volume of vapor = 45 mL = 0.045 L
Plug the values into the formula and you will get the vapor density of the substance. However, since we don't have the molar mass, we can't provide the final answer right now.
Please provide the molar mass or the identity/formula of the substance so that we can proceed with the calculation.
So this gas has a mass of 0.24g and a volume at NTP of 45 mL. What is the mass of H2 at NTP of 45 mL.
n of H2 = 0.045L/molar volume @ NTP = ?
Solve for n of H2.
Then n x molar mass H2 = grams.
v.d. = mass unknown gas/g H2 for that volume.
vapour density=vapour of gas/vapour of H2
vapour density =mass of 1L of vapour/mass of 1L of H2
massof 1L vapour= 0.24* 1000 kg
mass of 1L of H2 =vol*density =4580.089 kg
vapour density = 0.24*1000 /45*0.089=59.93