500g of copper is heated from 30 degree celcius to 120 degree celcius what is the quantity of heat supplied b.if the same quantity of heat is supplied to 300g of water initial at 30degree what will be the final temperature?
Q=mcdt=500/1000*400*(120-30)=18000J
To calculate the quantity of heat supplied, you can use the specific heat capacity formula:
Q = m * c * ΔT
Where:
Q is the quantity of heat supplied,
m is the mass of the substance,
c is the specific heat capacity of the substance, and
ΔT is the change in temperature.
For copper:
m = 500g (given)
c (specific heat capacity of copper) = 0.385 J/(g·°C) (approximate value)
ΔT (change in temperature) = (120°C - 30°C) = 90°C
Now, substitute these values into the formula:
Q = 500g * 0.385 J/(g·°C) * 90°C
= 17325 J
Therefore, the quantity of heat supplied to 500g of copper is 17325 Joules.
Now, let's calculate the final temperature of 300g of water after supplying the same quantity of heat.
For water:
m = 300g (given)
c (specific heat capacity of water) = 4.18 J/(g·°C) (approximate value)
Q = 17325 J (from the previous calculation)
Now, rearrange the formula to solve for ΔT:
ΔT = Q / (m * c)
Substitute the values into the formula:
ΔT = 17325 J / (300g * 4.18 J/(g·°C))
≈ 13.14°C
Therefore, the final temperature of the water will be approximately:
Initial temperature + ΔT = 30°C + 13.14°C
Final temperature ≈ 43.14°C
Hence, the final temperature after supplying the same quantity of heat to 300g of water initially at 30°C would be approximately 43.14°C.