A 25.0 g silver spoon at 20.0 C is placed in a cup of coffee initially at 90 C. How much heat does the spoon absorb from the coffee as the spoon warms up to 89 C? (C Silver - 230 J/kg C) Show all work.
193.2cal
To find the amount of heat absorbed by the silver spoon, we can use the formula:
Q = m * c * ΔT
Where:
Q is the amount of heat absorbed (in Joules),
m is the mass of the silver spoon (in kg),
c is the specific heat capacity of silver (in J/kg°C), and
ΔT is the change in temperature (in °C).
First, let's convert the mass of the silver spoon from grams to kilograms:
25.0 g = 0.025 kg
Next, we can calculate the change in temperature:
ΔT = T_final - T_initial
ΔT = 89°C - 20°C
ΔT = 69°C
Now we can substitute the values into the formula:
Q = (0.025 kg) * (230 J/kg°C) * (69°C)
Q ≈ 388.35 J
Therefore, the silver spoon absorbs approximately 388.35 Joules of heat from the coffee as it warms up to 89°C.