What is the discriminant of the polynomial below?

4x2 + 4x + 1

A. 0
B. -4
C. -12
D. 32

The discriminant of a quadratic polynomial in the form ax^2 + bx + c is given by the formula:

Discriminant = b^2 - 4ac.

In this case, the quadratic polynomial is 4x^2 + 4x + 1, so we can identify that a = 4, b = 4, and c = 1.

Now let's substitute these values into the discriminant formula:

Discriminant = (4)^2 - 4(4)(1)
Discriminant = 16 - 16
Discriminant = 0

Therefore, the discriminant of the polynomial 4x^2 + 4x + 1 is 0.

So the answer is (A) 0.

To find the discriminant of a quadratic polynomial, you need to use the formula:

Discriminant = b^2 - 4ac

In this case, the polynomial is

4x^2 + 4x + 1

So, a = 4, b = 4, and c = 1.

Substituting the values into the formula, we get:

Discriminant = (4)^2 - 4(4)(1)
= 16 - 16
= 0

Therefore, the discriminant of the given polynomial is 0.

Hence, the correct answer is A. 0.

the descriminant of

ax^2+bx+c

is always b^2-4ac

So, what do you think now?