What is the discriminant of the polynomial below?
4x2 + 4x + 1
A. 0
B. -4
C. -12
D. 32
The discriminant of a quadratic polynomial in the form ax^2 + bx + c is given by the formula:
Discriminant = b^2 - 4ac.
In this case, the quadratic polynomial is 4x^2 + 4x + 1, so we can identify that a = 4, b = 4, and c = 1.
Now let's substitute these values into the discriminant formula:
Discriminant = (4)^2 - 4(4)(1)
Discriminant = 16 - 16
Discriminant = 0
Therefore, the discriminant of the polynomial 4x^2 + 4x + 1 is 0.
So the answer is (A) 0.
To find the discriminant of a quadratic polynomial, you need to use the formula:
Discriminant = b^2 - 4ac
In this case, the polynomial is
4x^2 + 4x + 1
So, a = 4, b = 4, and c = 1.
Substituting the values into the formula, we get:
Discriminant = (4)^2 - 4(4)(1)
= 16 - 16
= 0
Therefore, the discriminant of the given polynomial is 0.
Hence, the correct answer is A. 0.
the descriminant of
ax^2+bx+c
is always b^2-4ac
So, what do you think now?