consider mixing 3.5L of co2 and 1.8L of h2o at 35C and 740mm Hg. determine the mass of the unbalanced reaction.
CO2 + H2O = C4H10 + O2
Use PV = nRT and solve for n CO2 (mols CO2). Do the same for n H2O.
The wording is confusing. Do you want the mass of the reaction as is or do you want it balanced first. I would think balanced first, then the mass of the balanced equation. If so, then
balance the equation.
Use mols of each to determine the limiting reagent, use stoichiometry to determine mols of each product formed, then convert to grams of each. Finally, add the grams for the total mass.
To determine the mass of the unbalanced reaction, we first need to calculate the number of moles of CO2 and H2O in the given mixture.
Step 1: Convert the volumes of CO2 and H2O to moles.
To do this, we need to know the molar volume of each gas. For CO2, the molar volume is 22.4 L/mol, and for H2O, it is 18.0 L/mol.
For CO2:
Number of moles of CO2 = volume of CO2 / molar volume of CO2
= 3.5 L / 22.4 L/mol
For H2O:
Number of moles of H2O = volume of H2O / molar volume of H2O
= 1.8 L / 18.0 L/mol
Step 2: Calculate the mass of CO2 and H2O.
To do this, we need to know the molar mass of each compound. The molar mass of CO2 is 44.01 g/mol, and for H2O, it is 18.02 g/mol.
For CO2:
Mass of CO2 = number of moles of CO2 * molar mass of CO2
For H2O:
Mass of H2O = number of moles of H2O * molar mass of H2O
Step 3: Find the total mass of the unbalanced reaction.
Since we know the balanced equation, we can find the stoichiometric coefficients for CO2 and H2O. According to the equation, the stoichiometric coefficient for CO2 is 1, and for H2O, it is 1.
Therefore, the total mass of the unbalanced reaction will be the sum of the masses of CO2 and H2O.
Total mass of the unbalanced reaction = Mass of CO2 + Mass of H2O
With these calculations, you will be able to determine the mass of the unbalanced reaction involving CO2 and H2O.