How many grams of aspirin are present in 0.50 mole of aspirin?

The chemical formula of aspirin is C9H8O4.

The molecular weight of aspirin is therefore 180 g/mol.
To get the grams of aspirin in the problem, just multiply the moles given by the molecular weight (to cancel units).

Hope this helps~ `u`

To determine the number of grams of aspirin present in 0.50 mole of aspirin, we need to use the molar mass of aspirin.

The molar mass of aspirin (C9H8O4) is calculated by adding up the atomic masses of all the elements in its chemical formula:
Molar mass of C (carbon) = 12.01 g/mol
Molar mass of H (hydrogen) = 1.01 g/mol
Molar mass of O (oxygen) = 16.00 g/mol

Therefore, the molar mass of aspirin is:
(9 * 12.01 g/mol) + (8 * 1.01 g/mol) + (4 * 16.00 g/mol) = 180.16 g/mol

To find the number of grams in 0.50 mole of aspirin, we can use the mole-to-gram conversion:
0.50 moles * 180.16 g/mol = 90.08 grams

Therefore, there are 90.08 grams of aspirin in 0.50 mole of aspirin.

To determine the number of grams of aspirin present in 0.50 mole of aspirin, we need to use the molar mass of aspirin.

The molar mass of aspirin (C9H8O4) can be calculated by summing the atomic masses of its constituents:

C: (12.01 g/mol) x 9 = 108.09 g/mol
H: (1.008 g/mol) x 8 = 8.064 g/mol
O: (16.00 g/mol) x 4 = 64.00 g/mol

Adding these values together, we find that the molar mass of aspirin is 180.15 g/mol.

Next, we can use the conversion factor:

1 mole of aspirin = 180.15 grams of aspirin

Therefore, 0.50 mole of aspirin is equal to:

0.50 mole x 180.15 g/mole = 90.08 grams of aspirin

So, 0.50 mole of aspirin contains 90.08 grams of aspirin.