A tank contained 22.5m^3 of water. More water was poured into the tank at the rate of 1.45m^3 per minutes. The tank was full at the end of 30 minutes. What is the capacity of the tank in tank?
=22.5 + 1.45(30)
=22.5 +43.5
= 66
= 66 * 1000 = 66000 liters
capacity=22.5+ 1.45*30 m^3
What is the volume of a retangle pyramid with a height of 12 in length of 10in and width of 8in
To find the capacity of the tank in liters, you can use the formula: capacity = volume × conversion factor.
First, let's find the total volume of water that was poured into the tank. Since water was poured at a rate of 1.45m^3 per minute for a total of 30 minutes, the additional volume of water can be calculated as:
additional volume = rate × time = 1.45m^3/min × 30 min = 43.5m^3.
Next, we can determine the total volume of water in the tank by adding the initial volume of water (22.5m^3) to the additional volume of water poured in:
total volume = initial volume + additional volume = 22.5m^3 + 43.5m^3 = 66m^3.
Now, to convert this capacity to liters, we need to use the conversion factor between cubic meters (m^3) and liters (L). The conversion factor is 1m^3 = 1000L. Therefore, the capacity of the tank in liters is:
capacity in liters = total volume × conversion factor = 66m^3 × 1000L/m^3 = 66000 liters.
So, the capacity of the tank is 66000 liters.