Physics

A baseball player leads off the game and hits a long home run. The ball leaves the bat
at an angle of 30.0o
from the horizontal with a velocity of 40.0 m/s. How far will it
travel in the air?

Working out please

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asked by Charles
  1. Vo = 40m/s[30o]
    Xo = 40*cos30 = 34.64 m/s.
    Yo = 40*sin30 = 20 m/s.

    Y = Yo + g*Tr = 0
    Tr = -20/-9.8 = 2.04 s. = Rise time.

    Y^2 = Yo^2 + 2g*h = 0
    h = -(Yo^2)/2g = -(20^2)/-19.6=20.4 m.

    h = 0.5g*t^2 = 20.4
    4.9t^2 = 20.4
    t^2 = 4.16
    t = 2.04 s. = Fall time(Tf).

    Range = Xo * (Tr+Tf)=34.64m/s * 4.08s. =
    141.3 m.

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    posted by Henry

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