The concentration of a solution made by diluting 10.0 mL of 0.685 mol/L NaBr to 300 mL is
0.685 mol/L x (10/300) = ?
To find the concentration of the final solution, we can use the formula for dilution:
C1V1 = C2V2
Where:
C1 = Initial concentration
V1 = Initial volume
C2 = Final concentration
V2 = Final volume
In this case, the initial concentration (C1) is 0.685 mol/L, and the initial volume (V1) is 10.0 mL. The final volume (V2) is given as 300 mL.
To find the final concentration (C2), we rearrange the formula:
C2 = (C1V1) / V2
Plugging in the values:
C2 = (0.685 mol/L * 10.0 mL) / 300 mL
First, we need to convert mL to L:
C2 = (0.685 mol/L * 0.010 L) / 0.300 L
Calculating:
C2 = 0.0228 mol/L
Therefore, the concentration of the solution made by diluting 10.0 mL of 0.685 mol/L NaBr to 300 mL is 0.0228 mol/L.