How many oxygen atoms are in 6Al (SO4)3
4 Oxygen x 3 = 12 in one molecule
12 x 6 molecules = 72 atoms of O
To determine the number of oxygen atoms in 6Al (SO4)3, we need to break down the formula and count the number of oxygen atoms present.
The formula 6Al (SO4)3 indicates that there are 6 aluminum (Al) atoms and 3 sulfate (SO4) groups. Each sulfate group consists of one sulfur (S) atom bonded to four oxygen (O) atoms.
Since there are 3 sulfate groups in the formula, the total number of sulfur atoms will be 3. And as each sulfate group contains 4 oxygen atoms, the total number of oxygen atoms will be 4 multiplied by 3, which equals 12.
Thus, there are 12 oxygen atoms in 6Al (SO4)3.
To determine the number of oxygen atoms in 6Al(SO4)3, we need to consider the individual components of the compound.
In the compound Al(SO4)3, there is one aluminum atom (Al) and three sulfate ions (SO4).
Each sulfate ion (SO4) consists of one sulfur atom (S) and four oxygen atoms (O).
So, in the compound Al(SO4)3, we have:
1 aluminum atom (Al)
3 sulfate ions (3 × (SO4))
3 sulfur atoms (3 × (S))
12 oxygen atoms (3 × (4 × O))
Adding all the oxygen atoms together, we get:
12 oxygen atoms
Therefore, there are 12 oxygen atoms in 6Al(SO4)3.