the perimeter of a rectangle is 62 m. The length is four more than two times the width. What is the length?
P = 2L + 2W
62 = 2(2W + 4) + 2W
62 = 6W + 8
54 = 6W
9 = W
9c
To find the length of the rectangle, we can start by setting up equations based on the given information.
Let's assume that the width of the rectangle is represented by the variable 'w'. According to the problem, the length is four more than two times the width, which can be expressed as (2w + 4).
The perimeter of a rectangle can be calculated by adding all four sides. In this case, the perimeter is given as 62 m. The formula for the perimeter is:
Perimeter = 2 * (length + width)
Substituting the given values, we have:
62 = 2 * ((2w + 4) + w)
Now, let's solve the equation to find the value of 'w'.
62 = 2 * (3w + 4)
62 = 6w + 8
Subtracting 8 from both sides:
54 = 6w
Dividing both sides by 6:
9 = w
So, the width of the rectangle is 9 meters.
To find the length, we can substitute the value of the width (w) into the expression for the length:
Length = 2w + 4 = 2 * 9 + 4 = 18 + 4 = 22
Therefore, the length of the rectangle is 22 meters.