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A mass of 5Kg is 1st weighed on a balance at the top of a tower 20m high.The man is then suspended from a fine wire 20m long and reweivhed.find the difference in a weight ,assuming that the radius of the earth is 6400km,the mass of the earth is 6×10^24kg and G=6.673×-11 Nm^2/Kg-2.

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Olushola

  1. Assume fine wire has zero mass
    Newton law of gravitation
    Weight=mg=GMm/r^2
    where units are in m, kg, seconds
    R1=6400000 (at top of tower)
    R2=(6400000-20)=6399980 (at bottom)
    M=6*10^24
    G=6.673*10^(-11)

    Difference in weight
    =GMm(1/R1^2-1/R2^2)
    Evaluate.

    Hint: the difference is less than a mN

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    MathMate

  2. Change in weight =3.06×10 ^-4 N

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    Kalpesh

  4. Bekar

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    Anonymous

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