Can anyone help me find the half-life of strontium-90? I also need an explanation on how to do it. Thanks!!
Radioactive Decay of Strontium-90:
At 0 years: 100% remaining
At 28 years: 50% remaining
At 56 years: 25% remaining
At 84 years: 10% remaining
At 112 years: 5% remaining.
To find the half-life of strontium-90, we can use the information provided about its radioactive decay. The half-life of a substance is the time it takes for half of the radioactive atoms to decay.
In this case, we can see that at 0 years, 100% of the strontium-90 is remaining. At 28 years, 50% of it remains, at 56 years, 25% remains, at 84 years, 10% remains, and at 112 years, 5% remains.
To find the half-life, we need to determine the time it takes for the amount of strontium-90 to decrease by half. Looking at the given data, we can see that it takes 28 years for the amount remaining to decrease from 100% to 50%, and another 28 years to decrease from 50% to 25%. This means that the half-life of strontium-90 is approximately 28 years.
To summarize, the half-life of strontium-90 can be determined by finding the time it takes for the amount remaining to decrease by half. In this case, it is approximately 28 years based on the given data.
Actually nevermind, I found the answer:
Half-life; 28.8 years. You can find the half-life of a substance by dividing the anount at one point in time by the amount remaining afterwards. Then multiply the elapsed time by the common log of 2 and by the amount of time that has gone by. Next just divide the number calculated in step 3 by the number in step 2.