How would you work the problem:
2 with the exponent of 4 minus 3 times 5 divided by 10 plus 16-15 divided by 10?
I would start out by rewriting it with parentheses in the approproate places.
2^4 - 3*5/10 + 16 - 15/10
The way you wrote it with no parentheses:
first the exponent:
16 - 3*5/10 + 16 - 15/10
now multiply and divide
16 - 1.5 + 16 - 1.5
now add and subtract
29
square root of 2a multipplied by the square root of 2a
I'm seriously having trouble in my algebra class, could you pleaaaaaaase help me.
(x+3)^4
To work out the problem, you will need to follow the order of operations, also known as PEMDAS (Parentheses, Exponents, Multiplication and Division from left to right, and Addition and Subtraction from left to right).
Step 1: Evaluate the exponent. Raise 2 to the power of 4.
2^4 = 2 * 2 * 2 * 2 = 16
Step 2: Perform the multiplication and division from left to right.
3 * 5 = 15
15 / 10 = 1.5
Step 3: Perform the addition and subtraction from left to right.
16 - 15 = 1
1 / 10 = 0.1
Step 4: Put all the results together.
16 - 1.5 + 0.1 = 14.6