What mass of water is needed to react com-
pletely with the Na2O2?
To determine the mass of water needed to react completely with Na2O2, we first need to calculate the stoichiometry of the reaction. The balanced equation for the reaction between Na2O2 and water (H2O) is:
2 Na2O2 + 2 H2O → 4 NaOH + O2
From the stoichiometry, we can see that for every 2 moles of Na2O2, we need 2 moles of water to react completely.
Now, if the molar mass of Na2O2 is M(Na2O2) and the molar mass of H2O is M(H2O), we can use these values to calculate the mass of water.
First, determine the molar mass of Na2O2 and H2O using their respective atomic masses:
M(Na2O2) = (2 * atomic mass of Na) + atomic mass of O2
M(H2O) = (2 * atomic mass of H) + atomic mass of O
Next, calculate the moles of Na2O2:
moles of Na2O2 = (mass of Na2O2 given) / M(Na2O2)
Since the stoichiometry tells us that the ratio of Na2O2 to H2O is 1:1, the moles of water needed will be equal to the moles of Na2O2:
moles of H2O = moles of Na2O2
Finally, calculate the mass of water:
mass of H2O = moles of H2O * M(H2O)
By following these steps and plugging in the necessary values, you can find the mass of water needed to react completely with Na2O2.