You count 9 cycles across 8.1 time divisions on an oscilloscope screen. The time sweep is set to 60 micro seconds. The voltage peak is measured to be 22 volts. What is the frequency?
You plot some data of Real Frequency versus HP Dial Frequency and get a linear trend of y = 1.09 x + 200. To what must you set the HP Dial Frequency in order to get a Real Frequency of 5660 [Hz]?.
To find the frequency in the first question, we can use the formula:
Frequency = Number of cycles / Time period
We are given that there are 9 cycles across 8.1 time divisions and the time sweep is set to 60 microseconds.
First, let's determine the time period:
Time period = Time sweep / Number of time divisions
Time period = 60 microseconds / 8.1 time divisions
Next, let's find the number of cycles in one time period:
Number of cycles = 9 cycles / 8.1 time divisions
Now let's substitute the values into the formula to calculate the frequency:
Frequency = 9 cycles / (60 microseconds / 8.1 time divisions)
Frequency = 9 cycles / (60e-6 s / 8.1)
Frequency ≈ 9 / 0.007407407 ≈ 1218.18 Hz
Therefore, the frequency is approximately 1218.18 Hz.
Now, let's move on to the second question:
Given the linear trend of y = 1.09x + 200, where y represents the Real Frequency and x represents the HP Dial Frequency, we can use this equation to find the HP Dial Frequency needed to achieve a Real Frequency of 5660 Hz.
Let's substitute the given Real Frequency into the equation and solve for x:
5660 = 1.09x + 200
Rearranging the equation to solve for x:
1.09x = 5660 - 200
1.09x = 5460
x = 5460 / 1.09
x ≈ 5018.35
So, in order to achieve a Real Frequency of 5660 Hz, you would need to set the HP Dial Frequency to approximately 5018.35 Hz.