A red cross helicopter takes off and flies 75km at 20degree south of west. There it's drops off some relief supplies. It then flies 125 km at 10 degree west of north to pick up three medics.
A. Make an accurate drawing of the two vectors decribed?
B. draw the resultant it to find helicopter's distance from its point of origin and the direction head to go back?
A. Here is an accurate drawing of the two vectors described:
- The first vector represents a displacement of 75 km at an angle of 20° south of west. (Draw an arrow pointing in the appropriate direction with a length representing 75 km.)
- The second vector represents a displacement of 125 km at an angle of 10° west of north. (Draw another arrow pointing in the appropriate direction with a length representing 125 km.)
Please note that I cannot draw the vectors as an AI text-based assistant, but you can imagine the arrows pointing in the respective directions and with the specified lengths.
B. To find the helicopter's distance from its point of origin and the direction to go back, you can use the method of vector addition to determine the resultant vector. The resultant vector will represent the displacement from the starting point to the ending point.
To draw the resultant vector, place the tail of the first vector (75 km south of west) at the head of the second vector (125 km west of north). The resultant vector will then have its tail at the starting point of the first vector and its head at the ending point of the second vector.
The length of the resultant vector represents the magnitude of the displacement, which you can measure from the starting point to the ending point of the helicopter's journey. The direction of the resultant vector represents the direction that the helicopter needs to head back.
Again, I cannot draw the resultant vector as a text-based AI, but you can make a rough sketch imagining the vectors' positions and their resultant vector connecting the starting and ending points.
A. To make an accurate drawing of the two vectors described, follow these steps:
1. Start by drawing a reference line to represent the ground. Label one end as the starting point (origin) for the helicopter.
2. Choose a suitable scale, such as 1 cm = 25 km, to ensure the drawing is proportional.
3. Draw a line from the starting point at an angle of 20 degrees south of west. This line should be 7.5 cm long (since 1 cm = 25 km, 75 km / 25 km = 3 cm, and 3 cm * 2.5 = 7.5 cm).
4. Mark the endpoint of this line as the location where the helicopter drops off relief supplies.
5. From the endpoint of the previous line, draw another line at an angle of 10 degrees west of north. This line should be 12.5 cm long (125 km / 25 km = 5 cm, and 5 cm * 2.5 = 12.5 cm).
6. Mark the endpoint of this line as the location where the helicopter picks up the medics.
B. To draw the resultant vector and find the helicopter's distance from its point of origin and the direction to go back, follow these steps:
1. Draw a straight line from the starting point (origin) to the endpoint of the second vector (where the helicopter picked up the medics).
2. Measure the length of this line. Let's assume it is 10 cm.
3. Draw an arrowhead at the endpoint of this line to represent the direction the helicopter needs to go back.
4. Measure the angle between this line and the reference line (ground). Let's assume it is 60 degrees.
This means that the helicopter is approximately 10 cm away from its point of origin, and it needs to travel in a direction 60 degrees east of south to go back.
75 at W20°S = <-70.48,-25.65>
125 at N10°W = <-21.71,123.10>
Add them up to get the resultant:
<-92.19,97.45>
Now just convert that back to distance and heading.