2. Perform this operation and report the answer to the correct number of significant figures: What is the mass of a cube of aluminum that is 4.0 cm on each edge? The density of aluminum is 2.7 g/cm3. Show all calculations leading to an answer.
(I think I solved this correctly but I would like to check, also I
mass=density*volume=2.7*4.0^3 to two significant figures.
To find the mass of the aluminum cube, we need to use the formula:
Mass = density × volume
First, let's calculate the volume of the cube:
Volume = (Edge length)^3
Given that the edge length of the cube is 4.0 cm, we can substitute this value into the formula:
Volume = (4.0 cm)^3 = 4.0 cm × 4.0 cm × 4.0 cm = 64 cm^3
Next, we can substitute the volume (64 cm^3) and the density of aluminum (2.7 g/cm^3) into the mass formula:
Mass = 2.7 g/cm^3 × 64 cm^3 = 172.8 g
Therefore, the mass of the aluminum cube is 172.8 grams.
To find the mass of the cube, you can use the formula:
Mass = Density * Volume
1. Firstly, calculate the volume of the cube:
Volume = (Edge length)^3
In this case, the edge length is 4.0 cm.
So the volume is: Volume = (4.0 cm)^3 = 64.0 cm^3
2. Next, substitute the volume into the formula to find the mass:
Mass = Density * Volume
The density of aluminum is given as 2.7 g/cm^3.
Therefore, Mass = 2.7 g/cm^3 * 64.0 cm^3 = 172.8 g
The mass of the aluminum cube is 172.8 grams.
Since the density is given to three significant figures (2.7), and the edge length is given to two significant figures (4.0), the answer should be reported to two significant figures as well. Therefore, the mass of the aluminum cube should be reported as 170 grams.