A car covers half a distance at a velocity of 80km/h and the other half at 60km/h,what is the average velocity of the car?
figure the time for each. Let d be half the distance.
time1=d/80
time2=d/60
avgvelocity=2d/(time1+time2)
so figure that out, I recommend do the math on time1+time2 first, solve the fraction issue...
68.57Km/Hr
let X = distance; t1 = x/80*2; t2 =60*2; t = x/ V average.
t1 + t2 = t = x / V average
(x / 160) +(x / 130)= x / V average
x(1/160 + 1/120) = x /V average
x( .014583333) x/V average
( .014583333)= 1/ V average
V average = 1/ ( .014583333)
V average = 68.57 Km/Hr
To find the average velocity of the car, we need to calculate the total distance traveled and the total time taken.
Let's assume the total distance traveled by the car is D.
The car covers half the distance at a velocity of 80 km/h, which means it covers D/2 distance at this speed. The time taken to cover this distance can be calculated using the formula:
time = distance / velocity
So, the time taken to cover the first half of the distance is (D/2) / 80 = D/160 hours.
Similarly, the car covers the other half of the distance at a velocity of 60 km/h, so it covers D/2 distance at this speed. The time taken to cover this distance is (D/2) / 60 = D/120 hours.
Now, to find the total time taken to cover the entire distance, we need to add the times taken for each half of the distance:
Total time taken = D/160 + D/120 = (3D + 4D) / (3 * 160) = 7D / 480 = D / 68.57 hours
Finally, we can calculate the average velocity by dividing the total distance by the total time taken:
Average velocity = Total distance / Total time taken = D / (D / 68.57) = 68.57 km/h
Therefore, the average velocity of the car is 68.57 km/h.