a 0.5KG ball is drop at concrete incline which is 45 degree above the horizontal then bounces off with the speed of 5m/s due to the force applied on it what is the change in its momentum
To find the change in momentum of the ball, we need to calculate the initial momentum and the final momentum, and then subtract the initial momentum from the final momentum.
1. Calculate the initial momentum:
The initial momentum of an object can be calculated by multiplying its mass by its initial velocity.
Given:
Mass of the ball (m) = 0.5 KG
Initial velocity (v) = 0 m/s (since it is initially at rest)
The initial momentum (P_initial) = mass * velocity = 0.5 KG * 0 m/s = 0 KG⋅m/s
2. Calculate the final momentum:
The final momentum of the ball can be calculated by multiplying its mass by its final velocity.
Given:
Mass of the ball (m) = 0.5 KG
Final velocity (v) = 5 m/s
The final momentum (P_final) = mass * velocity = 0.5 KG * 5 m/s = 2.5 KG⋅m/s
3. Calculate the change in momentum:
The change in momentum is the difference between the final momentum and the initial momentum.
Change in momentum (ΔP) = P_final - P_initial = 2.5 KG⋅m/s - 0 KG⋅m/s = 2.5 KG⋅m/s
Therefore, the change in momentum of the 0.5 KG ball dropped at a concrete incline and bouncing off with a speed of 5 m/s due to the applied force is 2.5 KG⋅m/s.