Tn=3n-2
Find the first term,a;the common difference,d;and then find the 5th term.
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To find the first term (a) and the common difference (d) of the arithmetic sequence given by the formula Tn = 3n - 2, we need to match this formula with the general formula for an arithmetic sequence: Tn = a + (n - 1)d.
Comparing the two formulas, we can see that in the given sequence, the coefficient of n is 3, which corresponds to the common difference (d). The constant term -2 corresponds to the first term (a).
Therefore, we can conclude that the first term (a) is -2 and the common difference (d) is 3.
To find the 5th term (T5), we can substitute n = 5 into the formula Tn = 3n - 2:
T5 = 3(5) - 2
T5 = 15 - 2
T5 = 13
Therefore, the 5th term of the sequence is 13.
a = T1 = 3*1-2
d = T2-T1 = (3*2-2) - (3*1-2) = 3
T5 = 3*5-2