PreCalc.
 👍 0
 👎 0
 👁 226

 👍 0
 👎 0

 👍 0
 👎 0
Respond to this Question
Similar Questions

algebra
HYPERBOLA Q!! Find an equation for a horizontal hyperbola with vertices that are 20 units apart from each other and foci 30 units apart each other?? im lost on this any help is appreciated !!!
asked by please help !!! on June 8, 2018 
Algebra 2
A hyperbolic mirror can be used to take panoramic photos, if the camera is pointed toward the mirror with the lens at one focus of the hyperbola. Write the equation of the hyperbola that can be used to model a mirror that has a
asked by T on May 3, 2019 
Algebra
what is the equation of the hyperbola given that the perimeter of the central rectangle is 44 units and its vertices are (7, 0) and (7, 0)
asked by Anonymous on May 24, 2018 
Math Word Problem
A cross section of a nuclear cooling tower is a hyperbola with equation x^2/90^2y^2/130^2=1. The tower is 450ft tall and the distance from the top of the tower to the center of the hyperbola is half the distance from the base of
asked by John on April 29, 2009 
math
the vertices are at (2,1) and (2,7) and focus is at (2,*) write the equation of the hyperbola that meets each set of conditions. Is the asterisk supposed to be an 8? It has to be some number. I will set this up for you later of
asked by becky on January 4, 2007

Math
Write the equation of the hyperbola with the following info: The hyperbola has vertices (–2, 9) and (–2, 3) and foci (–2, 13) and (–2, –1);
asked by Dustin on October 14, 2017 
EASY MATH
Write the equation of a hyperbola with a center at (5, 3), vertices at (5, 5) and (5, 1) and covertices at (11, 3) and (1, 3).
asked by Vince on June 7, 2011 
Algebra
Find an equation of a hyperbola with vertices (0,3) and (−4,3) and e=3/2. Thank you
asked by Matt on November 15, 2016 
Math
All i need is an equation of the hyperbola. given that the center is at (2, 3), the vertices are at (2, 3) and (2,  9), and the foci are at (2, 3 ± 2√10).
asked by Anonymous on May 25, 2018 
algebra 2
Graph the equation. Identify the vertices, foci, and asymptotes of the hyperbola. Y^2/16x^2/36=1 I think....vertices (0,4),(0,4) foci??? asymptotes y=+/ 2x/3
asked by sam on April 27, 2012
You can view more similar questions or ask a new question.