What are the asymptotes of the hyperbola (x+1)^2/4 - (y-2)^2/1 =1
I'm homeschooled, so the concept is hard to grasp.
Show steps please.

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  1. as you know, the hyperbola

    x^2/a^2 - y^2/b^2 = 1

    has asymptotes of

    y = ± b/a x

    You have a=2, b=1, so the asymptotes have slope ±1/2.

    Also, your hyperbola is shifted, so its center is not at (0,0). Thus, your asymptotes are

    y-2 = 1/2 (x+1)
    y-2 = -1/2 (x+1)

    y = x/2 + 5/2
    y = -x/2 + 3/2

    google and wikipedia are your friends. A simple search will turn up many useful articles.

    Also, wolframalpha is very useful for solving equations and plotting graphs. For this one, see^2%2F4+-+%28y-2%29^2%2F1+%3D1+%2C+y+%3D+x%2F2+%2B+5%2F2%2C+y+%3D+-x%2F2+%2B+3%2F2

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  2. Thank you very much, I understand it a little bit better now...

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