A Frisbee is thrown horizontally with a speed of 12 m/s. If the Frisbee moves a horizontal distance of 15 m, how long will it stay in the air?
d = Xo*t = 15 m.
12t = 15
t = 1.25 s. = Fall time.
G: Vix=12m/s dx=15m
F: t=?
S: t=dx/Vix
=15m/12m/s
=1.25s
Why did the Frisbee join the circus? Because it wanted to become an Airborne Acrobat!
But let's get back to your question. To determine how long the Frisbee will stay in the air, we can use the equation:
distance = speed × time
Since the Frisbee is thrown horizontally, only affected by gravity, which provides a constant downward acceleration, we can ignore the vertical motion and focus on the horizontal distance traveled.
So, if the Frisbee covers a horizontal distance of 15 m and is thrown with a speed of 12 m/s, we can rearrange the equation to solve for time:
time = distance / speed
Plugging in the values:
time = 15 m / 12 m/s
Calculating this, we find that the Frisbee will stay in the air for approximately 1.25 seconds. Just enough time to impress the crowd with its aerial antics!
To determine the time the Frisbee stays in the air, we can use the horizontal distance and the horizontal speed.
Step 1: Identify the known variables:
- Horizontal speed (v): 12 m/s
- Horizontal distance (d): 15 m
Step 2: Use the formula to calculate the time:
Time (t) = Distance (d) / Speed (v)
Substituting the values into the formula:
t = 15 m / 12 m/s
Step 3: Calculate the time:
t = 1.25 s
Therefore, the Frisbee will stay in the air for approximately 1.25 seconds.
To find the time the Frisbee will stay in the air, we need to use the horizontal distance it travels and its initial speed. We can use the equation:
distance = speed × time
In this case, the distance is 15 m and the speed is given as 12 m/s. We can rearrange the equation to solve for time:
time = distance / speed
Substituting the given values into the equation:
time = 15 m / 12 m/s
Simplifying the units:
time = (15 m) / (12 m/s)
Dividing the distance by the speed:
time = 1.25 s
Therefore, the Frisbee will stay in the air for 1.25 seconds.