How much 12M HCl would you need to make 100.0 mL of 2M HCl?

Use the dilution formula

mL1 x M1 = mL2 x M2

.016666666mL times 1,000. Equals 16.6 L

Can you show me how to set it up

To determine the amount of 12M HCl needed to make 100.0 mL of 2M HCl, we can use the concept of molarity and the equation:

M1V1 = M2V2

Where:
M1 = initial molarity of the solution (12M)
V1 = initial volume of the solution (unknown)
M2 = final molarity of the solution (2M)
V2 = final volume of the solution (100.0 mL)

Rearranging the equation to solve for V1:

V1 = (M2 * V2) / M1

Now let's substitute the known values into the equation:

V1 = (2M * 100.0 mL) / 12M

Simplifying the equation:

V1 = 200.0 mL / 12

V1 = 16.67 mL

Therefore, you would need approximately 16.67 mL of 12M HCl to make 100.0 mL of 2M HCl.