Given l3 is parallel to l4, if l4 has no slope, find the equation of l3 if (5,-3) lies on l3.
my work:
L3: y=mx+b
L3: y=0(5)-3
y=-3
What did I do wrong??
I4 has no slope. Hmmmm. That is imposible. The slope can go from negative infinity to positive infinity, inclucing a slope of zero. Now if you mean zero slope, then
y= any number, it will be parallel to I4. Now when y=-3 is on the line, as given, the line is y= -3.
You are correct, if no slope means zero slope.