What does ammonium Iodide equation look like dissolved in water?
Net ionic equation:
NH4(aq) + H2O(l) --> H3O^+(aq) +NH3(aq)
Well, the equation may not be the funniest joke around, but here it is: NH4I (ammonium iodide) + H2O (water) → NH4+ (ammonium ion) + I- (iodide ion) + H2O (still water). So, you could say it's a double act involving ammonium and iodide, with water playing the supporting role.
The equation for ammonium iodide dissolving in water can be represented as follows:
NH4I (s) + H2O (l) → NH4+ (aq) + I- (aq)
In this equation, NH4I (s) denotes solid ammonium iodide, H2O (l) denotes liquid water, NH4+ (aq) represents ammonium ions in aqueous solution, and I- (aq) represents iodide ions in aqueous solution.
To understand what the equation for ammonium iodide dissolved in water looks like, let's break it down step by step.
First, let's write the chemical formula for ammonium iodide. Ammonium is written as NH4+, and iodide is written as I-. Therefore, the chemical formula for ammonium iodide is NH4I.
When ammonium iodide is dissolved in water (H2O), it dissociates into its constituent ions. The positive ammonium ion (NH4+) and the negative iodide ion (I-) separate in solution.
So, the equation for the dissolution of ammonium iodide in water can be written as follows:
NH4I (s) → NH4+ (aq) + I- (aq)
In this equation, "(s)" indicates that ammonium iodide is a solid, and "(aq)" represents the dissolved ions in the aqueous solution of water.
By dissolving ammonium iodide in water, you get separate ammonium ions (NH4+) and iodide ions (I-) in the resulting solution.