What is the percentage of nitrogen in N2O?
63.648% this is my answer
[(2*atomic mass N/molar mass O2)]*100 = ?
Is that your answer? The molar mass N2O was not the question.
I have the same answer and that will be ok. If your prof is picky about significant figures s/he may have issue depending upon the numbers you used to make that calculation.
To find the percentage of nitrogen in N2O (nitrous oxide), you need to first calculate the molar mass of nitrogen and nitrous oxide, and then use this information to calculate the percentage.
The atomic mass of nitrogen (N) is around 14.01 g/mol. Nitrous oxide (N2O) consists of two nitrogen (N) atoms and one oxygen (O) atom.
First, calculate the molar mass of nitrous oxide (N2O):
Molar mass of N2O = (2 × molar mass of N) + (1 × molar mass of O)
= (2 × 14.01 g/mol) + (1 × 16.00 g/mol)
= 28.02 g/mol + 16.00 g/mol
= 44.02 g/mol
Next, calculate the molar mass of nitrogen in N2O:
Molar mass of nitrogen = 2 × molar mass of N
= 2 × 14.01 g/mol
= 28.02 g/mol
To find the percentage of nitrogen in N2O, divide the molar mass of nitrogen by the molar mass of nitrous oxide and multiply by 100:
Percentage of nitrogen = (molar mass of nitrogen / molar mass of N2O) × 100
= (28.02 g/mol / 44.02 g/mol) × 100
≈ 63.6%
Therefore, the percentage of nitrogen in N2O is approximately 63.6%.