You have a solution that contains 5.0 g of oxalic acid dissolved in 150 mL of water. This solution is placed in a separatory funnel, and then 100 mL of diethyl either is added to the separatory funnel and an extraction is performed (diethyl ether and water are immiscible). Use the following constants to calculate how much oxalic acid is in each solvent after the extraction: solubility of acid in water= 9.5g/100mL and solubility of acid in ether= 16.9 g/100mL

Do you have a K. I usually use them as g/g and if your prof does the same, then Ko/a = K(16.9/9.5) = 1.78

Then K = (concn organic phase/concn aqueous phase). Let x = g in organic phase, then 5-x = g in aqueous phase.
For org phase you have x/100
For aqueous phase you have (5-x)/150
Solve for x and 5-x

To calculate how much oxalic acid is in each solvent after the extraction, we need to consider the solubility of the acid in water and ether.

1. Calculate the amount of oxalic acid dissolved in water:
- Initial amount of oxalic acid in water = 5.0 g (given)
- Volume of water used = 150 ml

The solubility of oxalic acid in water is 9.5 g/100 ml. Therefore, we can calculate the amount of oxalic acid dissolved in water using the following proportion:

(Amount of oxalic acid in water) / (Volume of water) = (Solubility of acid in water) / (Volume of solution)

=> (Amount of oxalic acid in water) / 150 ml = 9.5 g/100 ml

Solving for (Amount of oxalic acid in water):

Amount of oxalic acid in water = (9.5 g/100 ml) * 150 ml
= (9.5 / 100) * 150
= 14.25 g

Therefore, after the extraction, there will be 14.25 g of oxalic acid in the water layer.

2. Calculate the amount of oxalic acid dissolved in diethyl ether:
- Initial amount of oxalic acid in solution = 5.0 g (given)
- Volume of diethyl ether used = 100 ml

The solubility of oxalic acid in diethyl ether is 16.9 g/100 ml. Using the same proportion as before:

(Amount of oxalic acid in diethyl ether) / (Volume of diethyl ether) = (Solubility of acid in ether) / (Volume of solution)

=> (Amount of oxalic acid in diethyl ether) / 100 ml = 16.9 g/100 ml

Solving for (Amount of oxalic acid in diethyl ether):

Amount of oxalic acid in diethyl ether = (16.9 g/100 ml) * 100 ml
= (16.9 / 100) * 100
= 16.9 g

Therefore, after the extraction, there will be 16.9 g of oxalic acid in the diethyl ether layer.

To calculate how much oxalic acid is in each solvent after the extraction, we need to determine the amount of oxalic acid that remains in the water layer and the amount that transfers to the ether layer.

First, let's calculate the amount of oxalic acid that can dissolve in 150 mL of water based on the solubility provided. Given the solubility of oxalic acid in water is 9.5 g/100 mL, we can calculate:

Amount of oxalic acid in water = (solubility of acid in water/100 mL) * (volume of water)
= (9.5 g/100 mL) * (150 mL)
= 14.25 g

Therefore, there are 14.25 g of oxalic acid initially present in the water layer.

Next, let's determine the amount of oxalic acid that can dissolve in 100 mL of diethyl ether using the provided solubility. Given the solubility of oxalic acid in ether is 16.9 g/100 mL, we can calculate:

Amount of oxalic acid in ether = (solubility of acid in ether/100 mL) * (volume of ether)
= (16.9 g/100 mL) * (100 mL)
= 16.9 g

Therefore, there are 16.9 g of oxalic acid initially present in the ether layer.

After performing the extraction, the oxalic acid will distribute between the water and ether layers based on their respective solubilities. The total amount of oxalic acid remains constant, but the distribution changes.

To calculate the amount of oxalic acid remaining in the water layer, we subtract the amount of oxalic acid transferred to the ether layer from the initial amount:

Amount of oxalic acid in water after extraction = Initial amount of oxalic acid in water - Amount of oxalic acid transferred to ether
= 14.25 g - (100 mL / 250 mL) * 14.25 g
= 14.25 g - 5.7 g
= 8.55 g

Therefore, after the extraction, there is 8.55 g of oxalic acid left in the water layer.

To calculate the amount of oxalic acid in the ether layer after the extraction, we subtract the amount of oxalic acid retained in the water layer from the initial amount in the ether layer:

Amount of oxalic acid in ether after extraction = Initial amount of oxalic acid in ether - Amount of oxalic acid retained in water
= 16.9 g - 8.55 g
= 8.35 g

Therefore, after the extraction, there is 8.35 g of oxalic acid in the ether layer.

In summary, after the extraction, there is approximately 8.55 g of oxalic acid in the water layer and 8.35 g of oxalic acid in the ether layer.