Ok, I'm trying my best here, I'm learning, and I'm thinking I'm on a roll, until I can't get the right answer again.....

First.. the butane question

Calculate the mass of Butane needed to produce 82.7g Carbon dioxide.

2C4H10 +13 O2--->10H2O +8CO2

Ratio is 2 C4H10 to 8 CO2
82.7 g/molar mass of CO2 44 = 1.88g/mol
but it's asking about butane
1.88 ( 2/8) = .47 and then .47 *58.12 = 27.3 I figured it out.. got the right answer .. But now on the next question it's asking for how many grams.. I'm confusing myself??

4Na+O2-->2Na2O

How many grams of Na2O are produced when 19.2 g. of Na reacts?
I started by getting moles..
19.2/22.9=.84 mols Na
.84(4/2)=1.68 then I did 1.68 *61.8 (molar mass of Na2O) and that was not the right answer... UGH!!! the right answer is 25.9 g somehow, and I can't figure out how.?

You stuck in numbers with the Na2O question without showing the units and you reversed the factor. The units are not there and that's why you can't find the error.

First I would not have rounded the 0.84 but kept 0.838. Why throw a perfectly good digit away. You have three digits in 19.2 so you should keep at least 3 in the answer. In fact, I usually keep an extra digit (as a guard digit) so I just leave that value in my calculator as 0.8384 and multiply that by the conversion factor.
0.8384 mols Na x (2 mols Na2O/4 molls Na) and that x (62 g Na2O/mol Na2O = about 26 grams. THEN you count the digits and round to the right number of significant figures.

Don't worry, I'm here to help you figure out the problem. Let's break it down step by step.

In the given balanced equation, 4Na + O2 → 2Na2O, we can see that the ratio between Na (sodium) and Na2O (sodium oxide) is 4:2.

First, you correctly calculated the number of moles of Na by dividing the given mass (19.2 g) by its molar mass (22.9 g/mol), giving you 0.84 mol of Na.

Next, you tried to use the stoichiometry (the ratio of coefficients) to find the number of moles of Na2O produced. However, you made a mistake in the calculation. Since the ratio of Na2O to Na is 2:4, you should multiply the moles of Na by (2/4) instead of (4/2). Therefore, 0.84 mol Na * (2/4) = 0.42 mol Na2O.

To find the mass of Na2O produced, multiply the number of moles of Na2O by its molar mass (61.8 g/mol).

0.42 mol Na2O * 61.8 g/mol = 25.9 g Na2O.

So the correct answer is indeed 25.9 grams of Na2O.

Mistakes happen, and it's important to double-check calculations to ensure accuracy. Keep up the good work and continue to practice these types of problems.