How can you graph y=2X +0.5 and y=0.5+1?

Thank you

I meant y=0.5x+1

In general, the line

y=ax+b
is in the slope intercept form, meaning that a=slope of the line, and b=y-intercept.

For example,
y=x+2
will have a line that has y-intercept =2 (i.e. the point (0,2)) and a slope of 1.
So graph a point at (0,2), and draw the remaining line passing through (0,2) with a slope of 1.

To graph y = 2x + 0.5 and y = 0.5 + 1, you can follow these steps:

1. Start by understanding the given equations. The equation y = 2x + 0.5 is in slope-intercept form (y = mx + b), where m represents the slope (2 in this case) and b represents the y-intercept (0.5 in this case). The equation y = 0.5 + 1 can be simplified to y = 1.5, where y remains constant.

2. Choose several x-values, and substitute them into the equations to find the corresponding y-values. Let's choose the x-values -2, 0, and 2 for simplicity.

For y = 2x + 0.5:
- When x = -2: y = 2(-2) + 0.5 = -4 + 0.5 = -3.5
- When x = 0: y = 2(0) + 0.5 = 0 + 0.5 = 0.5
- When x = 2: y = 2(2) + 0.5 = 4 + 0.5 = 4.5

For y = 0.5 + 1:
- When x = -2: y = 0.5 + 1 = 1.5
- When x = 0: y = 0.5 + 1 = 1.5
- When x = 2: y = 0.5 + 1 = 1.5

3. Plot the points on a graph using the chosen x and y values.

For y = 2x + 0.5:
- When x = -2, y = -3.5: plot the point (-2, -3.5)
- When x = 0, y = 0.5: plot the point (0, 0.5)
- When x = 2, y = 4.5: plot the point (2, 4.5)

For y = 0.5 + 1:
- When x = -2, y = 1.5: plot the point (-2, 1.5)
- When x = 0, y = 1.5: plot the point (0, 1.5)
- When x = 2, y = 1.5: plot the point (2, 1.5)

4. Connect the points with a straight line for each equation.

For y = 2x + 0.5: Draw a line that passes through (-2, -3.5) and (2, 4.5).
For y = 0.5 + 1: Draw a horizontal line at y = 1.5, since the y-coordinate remains constant.

The resulting graph will include two lines. One line will have a slope of 2 and intersects the y-axis at 0.5. The other line will be a horizontal line at y = 1.5.